Question

решите уровнение пж..........

Answer 1

   
Enuntul tau tradus este:  "Rezolba ecuatia..... x² - 2x - 35 = 0" 

Rezolvare:


[tex]\displaystyle\\ x_{12} = \frac{-b \pm \sqrt{b^2-4ac} }{2a} = \frac{2 \pm \sqrt{2^2+4\cdot 35} }{2} =\frac{2 \pm \sqrt{144} }{2} =\frac{2 \pm 12 }{2} \\\\ x_1 = \frac{2 + 12 }{2} =\frac{14 }{2} =\boxed{7}\\\\ x_2= \frac{2 - 12 }{2} =\frac{-10 }{2} =\boxed{-5}[/tex]