Question

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Answer 1

unghiurile unui triunghi dreptunghic in progresie aritmetica au masurile de

30°, 60°, 90°, cateta opusa uhghiului de 30° c1= ipotenuza/2=10/2=5cm,

Pitagora ptr a afla a doua cateta, c2²=10²-5²=100-25=75, c2=√75=5√3

perimetrulΔ=10+5+5√3=15+5√3=5(3+√3)

ariaΔ=c1*c2/2=5*5√3/2=25√3/2=12.5√3