Question

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Answer 1

Avem v, Ec=Ep/2 .

Se cere h la care energia cinetica este jumatate din energia potentiala.

$E_{mi} =E_{c} +E_{p}$

$E_{mi} =\frac{mv_0^{2} }{2}$

=>$\frac{mv_0^{2} }{2} =E_{c} +E_{p}$

Dar Ec=Ep/2 =>

$\frac{mv_o^{2} }{2} =\frac{Ep}{2} +Ep \\Aducem la acelasi numitor si obtinem\\ \\mv_0^{2} =3Ep\\mv_0^{2} =3mgh \\\\ h=\frac{v_0^{2} }{3g}$