Question

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Answer 1

-calculez masa de substanta pura

p=m,px100/ m,i----> mp= 1000x80/100g= 800g MgCO3 pur

M,MgCO3= 84g/mol

M,MgO= 40g/mol

M,CO2=44g/mol

M,MgCl2=95g/mol

M,CaCO3=100g/mol

84g.......................40g.........44g

MgCO3-------> MgO   + CO2

800g.....................x..............y               x= 381g            y=419g

40g............................95g

MgO    +  2HCl----> MgCl2   +  H2O

381g....................................x                         x=905gMgCl2

44g.....................................100g

CO2   + Ca(OH)2-----> CaCO3  + H2O

419g..................................x                               x= 952g CaCO3