Question

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Answer 1

Răspuns:

f(x)=(2x-3)/5

a) f(x)=0

(2x-3)/5=0

2x-3=0 x=3/2 A(3/2;0)

Int cu   Oy f(0)=(2*0-3)/5=-3/5

B( -3/5,0)

Trasezi dreapta   AB

b)f(x)=6+x+f(9)

(2x-3)/5=6+x+(2*9-3)/5

2x-3=6*5+5x+15

2x-5x=3+30+15

-3x=48

x=48/(-3)=-16

Explicație pas cu pas: