Question

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Answer 1

notam cu

x = nr. moli Na2O

y = nr. moli CaO

stim Na2O = 62 g/mol, CaO = 56 g/mol

62x + 56y = 18 g amestec

100% amestec................................ 26,666% O

(62x + 56y) g amestec ................ (16x+16y) g O

(62x + 56y)= 3,75.(16x+16y)

=> 2x = 4y

=> raportul molar x : y = 1 : 2

=> 62x + 56y = 18 => y = 0,1 moli Na2O

x = 0,2 moli CaO

=> 0,2x62 = 12,4 g Na2O

=> 0,1x56 = 5,6 g CaO