Question

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Answer 1

1+3+5+….+ab=[(ab+1)/2]²

[(ab+1)/2]²=(3a+2b)²

(ab+1)/2=3a+2b

ab+1=6a+4b

10a+b+1=6a+4b

4a+1=3b

=> a=2 si b=3

a=5 si b=7

ab={23; 57}

1+3+5+….+23=[(23+1)/2]²=144

(3a+2b)²=(6+6)²=144

1+3+5+….+57=[(57+1)/2]²=841

(3a+2b)²=(15+14)²=841