Question

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Answer 1

Ec Tg: y-f(x₀)= f`(x)(x-x₀)

Dar x₀ = -1 => ec tg: y-f(-1) = f`(-1)(x+1)

f(-1) = (-1)²-2*(-1) = 1+2 = 3

f`(x) = (x²-2x)` = 2x-2

f`(-1) = 2*(-1)-2 = -2-2 = -4

ec tg: y-3 = -4(x+1)

y-3 = -4x-4

y = -4x-1

-4x-1-y = 0 /*(-1)

4x+y+1 = 0

Answer 2

Răspuns:

Explicație pas cu pas:........................................