Question

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Answer 1

x mL sol H2SO4

stim ca Cm = roxc%x10/miu

=> c% = miuCm/10ro

= 98x9/10x1,47 = 60%

aplicam regula dreptunghiului:

c1=60% --------------------> 48-30 = 18 parti masice sol. c1%

            c.f.=48%

c2=30% -------------------> 60-48 = 12 parti masice sol. c2%

                        ---------------------------------------------------------

                 total parti masice = 18+12 = 30

30 parti ............. 18 parti sol. c1% ............... 12 parti sol. c2%

ms.tot  ............... ms1 .................................... 200 g

=> ms.tot = 30x200/12 = 500 g sol

=> ms1 = 18x200/12 = 300 g sol.

stim ca ro = ms/Vs = ms/x

=> x = ms1/ro = 300/1,47 = 204,08 mL sol. H2SO4