Question

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Answer 1

Răspuns:

a) AB=2√3 AC=4√2

${bc}^{2} = {ac}^{2} + {ab}^{2} \ \\ {bc}^{2} = {2 \sqrt{3} }^{2} + {4 \sqrt{2} }^{2} \\ bc = \sqrt{12 + 32} \\ bc = \sqrt{44} \\ bc = 2 \sqrt{11}$

b)BC=6√2 AB=4√3

${ac}^{2} = {bc}^{2} - {ab}^{2} \\ {ac}^{2} = {6 \sqrt{2}^{2} } - {4 \sqrt{3} }^{2} \\ ac = \sqrt{72 - 48} \\ ac = \sqrt{24} \\ ac = 2 \sqrt{6}$

c)BC=6√3 AC=2√11

${ab}^{2} = {bc}^{2} - {ac}^{2} \\ {ab}^{2} = {6 \sqrt{3}}^{2} - {2 \sqrt{11}}^{2} \\ ab = \sqrt{108 - 44} \\ ab = \sqrt{64} \\ ab = 8$