Question

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Answer 1

Răspuns:

Explicație:

1.

m= n . M

MHCl= 1 + 35,5= 36,5 ------> 36,5g/moli

m= 5moli .36,5g/moli= 182,5 g HCl

2.

MH2O= 18-----> 18g/moli

18H2O----------16g O

XgH2O---------32gO

X= 18 . 32 : 16=36 g H2O

n= 36g : 18g/moli= 2moli H2O

3.

MSO2 =32 + 32=64--------> 64g/moli

64g SO2--------32gS---------32gO

100--------------------X------------Y

X= 100.32 : 64 =50% S

Y= 100 . 32 : 64=50% O

4.

MCa(OH)2 =40 + 2.16 =2= 74--------> 74g/moli

74g Ca(OH)2---------40g Ca

xg---------------------------80gCa

x= 74 . 80 : 40 = 148 g Ca(OH)2

5.

234 gAl(OH)3

g Al2O3

M= 27 + 3.16 + 3=78--------> 78g/moli

-se afla g, moli Al din 234 g Al(OH)3

78 g Al(OH)3----------27g Al

234g----------------------------x

x= 234 . 27 : 78= 81g Al

n= 81g : 27g/moli= 3moli Al

MAl2O3= 54 + 48=102------> 102 g/moli

-se afla g,moli  Al2O3  care contin 81g Al  [ 3moli Al ]

102 g Al2O3------ 54gAl

yg--------------------------81gAl

y= 102 .81 : 54=153 g Al2O3

n= 153g : 102g/moli=1,5 moli Al2O3