Question

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Answer 1

$\frac{2}{\sqrt{12} } +\frac{5}{\sqrt{75} } -(\frac{3\sqrt{3} }{8} +\frac{6}{\sqrt{108} } )=\\\frac{2}{2\sqrt{3} } +\frac{5}{5\sqrt{3} } -(\frac{3\sqrt{3} }{8} +\frac{6}{6\sqrt{3} } =\\\frac{1}{\sqrt{3} } +\frac{1}{\sqrt{3} } -(\frac{3\sqrt{3} }{8} +\frac{1}{\sqrt{3} })=\\\frac{\sqrt{3} }{3} +\frac{\sqrt{3} }{3} -(\frac{3\sqrt{3} }{8} +\frac{\sqrt{3} }{3 })=\\\frac{\sqrt{3} }{3} +\frac{\sqrt{3} }{3} -(\frac{9\sqrt{3} }{24} +\frac{8\sqrt{3} }{24} )=$

$\frac{\sqrt{3} }{3} +\frac{\sqrt{3} }{3} -\frac{17\sqrt{3} }{24} =\\\frac{2\sqrt{3} }{3} -\frac{17\sqrt{3} }{24} =\\\frac{16\sqrt{3} }{24} -\frac{17\sqrt{3} }{24} =\frac{-\sqrt{3} }{24}$