Question

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Answer 1

Răspuns:

AB=c=2

AC=b=2√3

<B=π/3

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<C=?

Aplici teorema   sinusului

c/sin C=b/sin <B

2/sinc=2√3/sinπ/3

2/sinC=2√3/(√3)/2

2/sinC=2*2

2sinC=4

sinC=4/2=1/2=>

<C=π/6=>

<A=π-(π/3+π/6)=

π-3π/6=π-π/2=π/2

Triunghiul ABC dreptunghic in A

Aplici Pitagora

a²=b²+c²

a²=(2√3)²+2²=

4*3+4=16

a=√16

a=4

BC=4

Explicație pas cu pas: