Question

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Answer 1

Răspuns:

relatia utilizata

c,m= niu(n)/ Vs

2= 4/Vs----> Vs=4mol/2 mol/l=2 l

M,NaOH=40g/mol

niu(n)= m/M=16/40mol=0,4mol NaOH

Vs= niu/c,m= 0,4mol/0,2mol/l= 2 l

ro=m/v

n(niu)=2mol

ms=200g

v,s=m,s/ro=200g/1,84g/ml=108,7 ml= 0,1087 l

c,m=2mol/0,1087 l=18,4 mol/l

Explicație: