Question

0,(3);0,1 (6) si 0,(4) cu ponderile 3,15 si 9     
calculati media ponderata a numerelor:

Answer 1

0,(3)=3/9=1/3 ;   0,1(6)=(16-1) / 90 =15/90=1/6  si  0,(4)=4/9 ;

$m_p=\frac{\frac{1}{3}\cdot3+\frac{1}{6}\cdot15+\frac{4}{9}\cdot9}{3+15+9}=\frac{1+2,5+1}{27}=\frac{4,5}{27}\;=0,1(6)$