Question

[0,(3)+1,(3):1 7/9]:(1+1/12)

Answer 1

0,(3)=3/9=1/3
1,(3)=1 intreg 3/9=(1x9+3)/9=12/9=4/3
1 intreg 7/9=(1x9+7)/9=16/9
(1/3 + 4/3 : 16/9) : 13/12=
(1/3 + 4/3 x 9/16) x 12/13=
(1/3 + 3/4) x 12/13=
(4+9)/12 x 12/13=
13/12 x 12/13=
1

Answer 2

[0,(3)+1,(3):1 7/9]:(1+1/12)=

0,(3)=3/9;    1,(3)=(13-1)/9=12/9  ; 1 7/9=(1×9+7)/9=16/9

[3/9+12/9 :16/9]: (12+1)/12=

[1/3+4/3 ×9/16]: 13/12=

=(1/3+3/4)×12/13

=(4+9)/12×12/13

=13/12×12/13

=1