Question

[0,(3)+1,(3):1 intreg si 7 pe 9]:(1+1 pe 12

Answer 1

[(3-0)/9+(13-1)/9:(1×9+7)/9]:(1+1/12)=
(3/9+12/9:16/9):13/12=
(3/9+12/9×9/16):13/12=
(1/3+3×1/4):13/12=
(1/3+3/4):13/12=
(4+9)/12:13/12=
13/12:13/12=1