Question

{[0,(3)+3/11+1,(23)]:(45:0,09+2 intregi si2/3)}×1914​

Answer 1

Răspuns:

0,(3) = 3/9 = 1/31, (23)=(123-1)/99=122/99

0,09=9/100

{[0,(3)+ 3/11 + 1,(23) ] :(45: 0,09 +8/3)}x1914 =

= {[1/3+3/11+122/99:(45/1x100/9+8/3)}x1914=

={[(33+3x9+122)/99]:(4500/9+8/3)}x1914={182/99:(500+8/3)}x1914=

= {182/99:(1500+8)/3}x1914=(182/99:1508/3)x1914=

=182/99x3/1508x1914=91/33x1/754x1914/1=174174/24882=7