Question

{[0,(3)+ 3 supra 11 + 1,(23) ] :(45: 0,09 + 2 intregi 2 supra 3 )} ori 1914 =

Answer 1

0,(3)=3/9=1/31,(23)=(123-1)/99=122/99
0,09=9/100
{[0,(3)+ 3/11 + 1,(23) ] :(45: 0,09 +8/3)}x1914={[1/3+3/11+122/99]:(45/1x100/9+8/3)}x1914=
{[(33+3x9+122)/99]:(4500/9+8/3)}x1914=
{182/99:(500+8/3)}x1914=
{182/99:(1500+8)/3}x1914=
(182/99:1508/3)x1914=
182/99x3/1508x1914=91/33x1/754x1914/1=174174/24882=7