Question

0,3x>1,2×[0,2(7)x+0,(3)]​

Answer 1

Răspuns,explicație pas cu pas:

$0,3x>1,2x*(1,4x+o)$

[tex]0,3x>1,2x*1,4x\\ 0,3x>1,62^{2} [/tex]

$\frac{3}{10} x-\frac{42}{25} x^{2} >0$

[tex]15x-84x^{2} >0\\ 3x*(5-28x)>0[/tex]

$x*(5-28x)>0$

$\left \{ {{x>0} \atop {5-28x>0}} \right. \\\\\\left \{ {{x<0} \atop {5-28x<0}} \right.$ fara ,,left,, , nu stiu ce s a intamplat aici,iarta-ma

[tex]\left \{ {{x>0} \atop {x<\frac{5}{28} }} \right. \\ \\ \left \{ {{x>\frac{5}{28} } \atop {x>0}} \right. [/tex]

dupa avem intersectia care ne da:

x∈$(0,\frac{5}{28)}$