Question

01 Aflati numerele naturale a, b, c, a < b c
daca:
a) 70 + 7 + 7c = 21;
c) 80 + 8b + 8C = 48;
b) 5a + 5b + 5c = 20;
d) 3a + 6b + 9c = 42. Va rog ​

Answer 1

Răspuns:

a).7c=21-77

7c=-56

c=-8

c).80+8b+8x(-8)=48

80+8b-64=48

8b=48-16

8b=32

b=4

b). 5a+5x4+5x(-8)=20

5a+20-40=20

5a=20+20

5a=40

a=8

d). 3x8+6x4+9x(-8)=42

24+24-72=42

-24=42