Question

{1:[0,28+0,16):11 la puterea2 / 75 ] - 2/3}×7/3 VA ROG​

Answer 1

Răspuns:

7

Explicație pas cu pas:

{1 : [(0,28 + 0,16) : 11^2/75] - 2/3} × 7/3 =

= [1 : (0,44 : 11^2/75) - 2/3] × 7/3 =

= [1 : (44/100 : 11^2/75) - 2/3] × 7/3 =

= [1 : (11/25 × 75/11^2) - 2/3] × 7/3 =

= [1 : (1/1 × 3/11) - 2/3] × 7/3 =

= (1 : 3/11 - 2/3) × 7/3 =

= (1 × 11/3 - 2/3) × 7/3 =

= 9/3 × 7/3 =

= 3 × 7/3 =

= 7