Question

[1+(1+2+2^2+...+2^9)]× x=(2^3)^4÷2^2​

Answer 1

Răspuns:

progresie geometrica

r=2 a1=1. an=2^9

suma=(an.r-a1)/(1-r)=(2^9-1)(-1)

atunci (1+1-2^9)*x=2^12:2^2=2^10

x=2^10/2(1-2^9)=2^9/(1-2^9)