Matematică, întrebare adresată de caterinafeher, 9 ani în urmă

1. (1/2+2/3-3/4)^2-(1/2)^2-(2/3)^2-(-3/4)2-2*1/4*2/3-2*1/2*(-3/4)=?
2. 1-{[-2/3-5/21:(-1-3/7)]*11/2+3/5}:(-4 3/2)=?


Dau coroana!!!!Va rog ajutati-ma!!!

Răspunsuri la întrebare

Răspuns de renatemambouko
3
1. (1/2+2/3-3/4)²-(1/2)²-(2/3)²-(-3/4)²-2*1/4*2/3-2*1/2*(-3/4)=
=[
(6+8-9)/12]²-1/4-4/9-9/16-1/3+3/4=
=[(5/12]²-1/4-4/9-9/16-1/3+3/4=
=25/144-4/9-9/16-1/3+2/4=
=(25-64-81-48+72)/144=
=-96/144=-2/3


 2. 1-{[-2/3-5/21:(-1-3/7)]*11/2+3/5}:(-4 3/2)=
=
1-{[-2/3-5/21:(-10/7)]*11/2+3/5}:(-11/2)=
=1-{[-2/3+5/21×7/10)]*11/2+3/5} ×(-2/11)=
=1-{[-2/3+1/6)]*11/2+3/5} ×(-2/11)=
=1-{[-4/6+1/6)]*11/2+3/5} ×(-2/11)=
=1-[(-3/6)*11/2+3/5] ×(-2/11)=
=1-[(-1/2)*11/2+3/5] ×(-2/11)=
=1-[(-11/4+3/5] ×(-2/11)=
=1-[(-55+12)/20] ×(-2/11)=
=1-(-43/20) ×(-2/11)=
=1-(43/10) ×1/11)=
=1-43/110=
=(110-43)/110=67/110










caterinafeher: Multumesc mult!
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