Question

(1+ 1 supra 2)×(1+1 supra 3)×(1+ 1 supra 4)×...×(1+1 supra 50)=

Answer 1

[tex](1+\frac{1}{2})(1+\frac{1}{3})(1+\frac{1}{4})...(1+\frac{1}{50})=\\ \\ \frac{2+1}{2}\cdot \frac{3+1}{3}\cdot \frac{4+1}{4}\cdot...\cdot\frac{50+1}{50}=\\ \\ \frac{3}{2}\cdot\frac{4}{3}\cdot \frac{5}{4}\cdot...\cdot \frac{51}{50}=\boxed{\bold{\frac{51}{2}}}\\ [/tex]