Question

1. 1000 dam=? m 10000 dam=? m 12 km = ? m 2.500-286 900-373 9000-566 3.a+22=1000 5000-c=222 3000-k=890 4.La suma nr 500 si 30 adauga diferenta nr 900-123 5.Ma gandesc la un nr il adun cu 15 si obtin 5000 intrebare la ce nr m-am gandit? ofer coroana

Answer 1

1) 1000 dam= 10000 m10000 dam  =100000 m12 km  =12000 m
 2) 286 -2.500 =283,5900-373=5279000-566=84343) a+22=1000a=1000-22a=978
5000-c=222c=5000+222c=5222
3000-k=890+

Answer 2

1000 dam= 10000 m
10 000 dam = 100.000 m
12 km=12 000 m

500 - 286 =204
900 - 373=527
9000-566=8434

5000- c =222
c = 5000 - 222
c = 477

3000-k =890
k = 3000 - 890
k =2110

( 500 + 30) + (900 - 123) = 530 + 777=1307

a + 15 = 5000
a = 5000- 15
a = 9985