Matematică, întrebare adresată de Misahi, 9 ani în urmă

1/12 + 4/5 : ( 1/2-1/3)=

2: ( 2/3) la puterea a 2-a + 11/5:11/10=

(1/4+7/6)·15/34+3/2·( 1/3-1/21)=

(0,25) la puterea a 7-a· (0,25) la puterea 14 : (1/4) la puterea a 19 + 0,125=

0,5·[1/3+1/4- 0,1(6)] : 2,5=

6+11/5:(2 intregi 2/3 - 1 intreg 1/5) +1:[(5/3+1/7-2/21)·1/6]=


podeanutheodora: vrei rezolvari complete sau doar rezultatele?
Misahi: rezolvari complete :)

Răspunsuri la întrebare

Răspuns de podeanutheodora
12
1/12 + 4/5 : (1/2 - 1/3) = 1/12 + 4/5 : ( 3/6 - 2/6) = 1/12 + 4/5 : 1/6 = 1/12 + 4/5 x 6/1 = 1/12 + 24/5 = 5/60 + 288/60 = 293/60

2/1 : (2/3) la puterea a 2a + 11/5 : 11/10 = 2/1 : 4/9 + 11/5 x 10/11 = 2/1 x 9/4 + 10/5 = 9/2 + 2/1 = 9/2 + 4/2 = 13/2

(1/4 + 7/6) x 15/34 + 3/2 x (1/3 - 1/21) = (3/12 + 14/12) x 15/34 + 3/2 x (7/21 - 1/21) = 17/12 x 15/34 + 3/2 x 6/21 = 5/8 + 3/7 = 35/56 + 24/56 = 59/56

(0,25) la puterea a 7a x (0,25) la puterea a 14a : (1/4) la puterea a 19a + 0,125 = (0,25) la puterea 21 : (0,25) la puterea 19 + 0,125 = (0,25) la puterea a 2a + 0,125 = 0,0625 + 0,125 = 0,1875

0,5 x [1/3 + 1/4 - 0,1(6)] : 2,5 = 5/10 x (1/3 + 1/4 - 15/90) : 25/10 = 5/10 x (1/3 + 1/4 - 1/6) : 25/10 = 5/10 x (4/12 + 3/12 - 2/12) x 10/25 = 5/10 x 5/12 x 10/25 = 1/12

6 + 11/5 : (2 intregi 2/3 - 1 intreg 1/5) + 1: [(5/3 + 1/7 - 2/21) x 1/6] = 6/1 + 11/5 : (8/3 - 6/5) + 1/1 : [(35/21 + 3/21 - 2/21) x 1/6] = 6/1 + 11/5 : (40/15 - 18/15) + 1/1 : (36/21 x 1/6) = 6/1 + 11/5 : 22/15 + 1/1 : 6/21 = 6/1 + 11/5 x 15/22 + 1/1 x 21/6 = 6/1 + 3/2 + 21/6 = 36/6 + 9/6 + 21/6 = 66/6 = 11

Sper ca te-am ajutat! 
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