Question

( 1/√2 + 1)² + ( 1/√2 - 1)²- 1/2

Answer 1

mai intai trebuie sa folosesti formula: $(a+b)^{2} = a^{2} + b^{2} +2ab$ si $(a-b)^{2} = a^{2} -2ab+ b^{2}$

$(1/ \sqrt{2}+1)^{2} =(1/ \sqrt{2})^{2} +2/ \sqrt{2} +1^{2} =1/2+2/ \sqrt{2} +1$

$(1/ \sqrt{2} -1)^{2} =(1/ \sqrt{2})^{2} -2/ \sqrt{2}+1 =1/2-2/ \sqrt{2} +1$

1/2+2/$\sqrt{2}$+1+1/2-2/$\sqrt{2}$+1-1/2=1/2+2=5/2

Answer 2

( 1/√2 + 1)² + ( 1/√2 - 1)²- 1/2=(1/√2)²+2/√2+1+(1/√2)²-2/√2+1-1/2=1/2+2/√2+1+1/2-2/√2+1-1/2=1/2+1+1/2+1-1/2=1/2+1+1=1/2+2=5/2