Question

1+2{1+2[1+2(x-31)]+10}=115 aflati l pe x

Answer 1

1+2×{1+2×[1+2×(x-31)]+10}=115
2×{1+2×[1+2×(x-31)]+10}=115-1
2×{1+2×[1+2×(x-31)]+10}=114
1+2×[1+2×(x-31)]+10=114÷2
1+2×[1+2×(x-31)]+10=57
1+2×[1+2×(x-31)]=57-10
1+2×[1+2×(x-31)]=47
2×[1+2×(x-31)]=47-1
2×[1+2×(x-31)]=46
1+2×(x-31)=46÷2
1+2×(x-31)=23
2×(x-31)=23-1
2×(x-31)=22
x-31=22÷2
x-31=11
x=11+31
x=42