Question

[(1_2+1_21):(1_18+1_14)-2intreg1_2]×8

Answer 1

$(( \frac{1}{2} + \frac{1}{21} ) \div ( \frac{1}{18} + \frac{1}{14}) - 2 \frac{1}{2} ) \times 8$


$= ( \frac{21 + 2}{42} \div \frac{14 + 18}{252} - \frac{2 \times 2 + 1}{2} ) \times 8$
$= ( \frac{23}{42} \div \frac{32}{252} - \frac{5}{2} ) \times 8$

$= ( \frac{23}{42} \times \frac{252}{32} - \frac{5}{2} ) \times 8$
252se imparte la 42 si ramane 6


$= ( \frac{23 \times 6}{1 \times 32} - \frac{5}{2} ) \times 8$



$= ( \frac{138}{32} - \frac{5}{2}) \times 8 = \frac{138 - 16 \times 5}{32} \times 8$



$= \frac{138 - 80}{32} \times 8 = \frac{58}{32} \times 8 = \frac{58 \times 1}{4} =$
$= \frac{58}{4} \div |2| = \frac{29}{2}$