Question

1+2+2^2+2^3+2^4+2^5+2^6
1+2^-1+2^-2+2^-3

Answer 1

a) = 1+2+4+8+16+32+64 = 127
Asta se poate calcula asa

b)
$=1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3} \\ \\ =1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8} \\ \\ =1+0,5+0,25+0,125 \\ \\ =1,875$

Answer 2

ridici la putere fiecare nr, unde ai ex 2^-1=1/2^1=1/2 rastorni nr la 2^-2=1/2^2 =1/4 etc apoi ridici la aceasi putere si fractiile care iti rezulta si aduci la aceladi numitor apoi le aduni