Question

[(1/2+2/3+5/6):7/12-2/5×5/6]×1/4÷(5×12/25-1întreg și 1/3)

Answer 1

Răspuns:

Explicație pas cu pas:

1 intreg si 1 / 3 = ( 1 x 3 + 1 ) / 3 = 4 / 3

[ ( 1 / 2 + 2 / 3 + 5 / 6 ) : 7 / 12 - ( 2 / 5) × 5 / 6 ] × ( 1 / 4 ) : ( 12 / 5 - 4 /3) =

= [ ( 3 / 6 + 4 / 6 + 5 / 6 ) : 7 / 12 - 1 / 3 ] × 1 / 4 : ( 36 / 15  - 20 / 15 ) =

= [ ( 12 / 6 ) × 12 / 7 - 1 / 3 ] × 1 / 4 : ( 16 / 15 ) =

= ( 24 / 7 - 1 / 3 ) × 1 / 4 × ( 15 / 16 ) =

= ( 72 / 21 - 7 / 21 ) × 1 / 4 × ( 15 / 16 ) =

= ( 65 / 21 ) × 1 / 4 × ( 15 / 16 ) =

= ( 65 × 5 ) / ( 7 × 4 × 16 ) =

= 325 / 448