Question

1+2+3+4+.....2003= nustiu cica este cu formula lu gaus ma ajutati pls

Answer 1

$Formula~lui~Gauss= \frac{n(n+1)}{2} ,~unde ~n=ultimul~termen~ \\ \\ In~cazul~tau~n=2003 \\ S= \frac{2003*2004}{2} =2003*1002=2007006$

Answer 2

Formula lui Gauss: Sn= n*(n+1) /2 ; n este numarul de termeni.

1+2+3+4+.....2003= 2003*(2003+1) /2=2003*2004/2= 2003*1002= 2 007 006