Question

1+{2×[3+(4+y)÷5]-6}×7=29

Answer 1

{2x[3+(4+y)÷5]-6}x7=29-1
{2x[3+(4+y)÷5]-6}x7=28
2x[3+(4+y)÷5]-6=28÷7
2x[3+(4+y)÷5]-6=4
2x[3+(4+y)÷5]=6+4
2x[3+(4+y)÷5]=10
3+(4+y)÷5=10÷2
3+(4+y)÷5=5
(4+y)÷5=5-3
(4+y)÷5=2
4+y=2x5
4+y=10
y=10-4
y=6
Coroana???