Question

1+2*{3 la puterea 2+7*(x-3*5 la puterea 4)]}+1993 la puterea 0=1994

Answer 1

$1+2*[9+7(x-3*625)]+1=1994$

$1+2*[9+7(x-1875)]+1=1994$

$1+2*(9+7x-7*1875)+1=1994$

$1+2*(9+7x-13125)+1=1994$

$2+2*(7x-13116)=1994$

$2*(7x-13116)=1994-2$

$2*(7x-13116)=1992$

$7x-13116=\frac{1992 }{2}$

$7x-13116=996$

$7x=996+13116$

$7x=14112$

$x= \frac{14112}{7}$

$x=2016$