Question

1+{2×[3+(n-4)×5]÷6}×7=8

Answer 1

1+{2*[3+(n-4)*5]/6}*7=8
1+[2(3+5n-20)/6}*7=8
1+[2(-17+5n)/6]*7=8
1+$\frac{2(-17+5n)}{6}$ *7=8
1+$\frac{-17+5n}{3}$ *7=8
1+$\frac{7(-17+5n)}{3}$=8
1+$\frac{-119+35n}{3}$=8
3*1+3*$\frac{-119+35n}{3}$=3*8
3-119+35n=24
-116+35n=24
35n=24+116
35n=140
n=4