Question

1.(2^x)^5=1
2.(5 supra 3)totul la x la a doua minus 7x+12=1


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Answer 1

Răspuns:

Explicație pas cu pas:

(2ˣ)⁵ = 1 <=> 2⁵ˣ = 1 <=> 2⁵ˣ = 2⁰ =>

5x = 0 => x = 0

(5/3)ˣ²⁻⁷ˣ⁺¹² = 1  <=>

(5/3)ˣ²⁻⁷ˣ⁺¹² = (5/3)⁰ =>

x²-7x+12 = 0  =>

x₁,₂ = [7±√(49-48)]/2

x₁,₂ = (7±1)/2 =>

x₁ = 3 ; x₂ = 4