Question

1+21÷{1+[a+(a÷4-2)×2]÷7}=8​

Answer 1

Răspuns:

a=10

Explicație pas cu pas:

1+21:(1+(a+(a/4-2)×2):7)=8

1+21:(1+(a+(a-2/4)2)/7=8

21:(1+(a+a-2/2)×1/7)=7        21:(1+(2a+a-2/2×1/7))=7        3:(14+3a-2)14=1

3×14/(12+3a)=1         42=12+3a         30=3a       a=10

Answer 2

21÷{1+[a+(a÷4-2)×2]÷7}=7

3÷{1+[a+(a÷4-2)×2]÷7}=1

3=1+[a+(a÷4-2)×2]÷7

2*7=a+(a÷4-2)×2

14=a+a:2-4

18*2=2a+a

3*3*2*2=3a

a=12