Question

1. √2²*3²+3√576= (primul radical acopera tot ex)
2.√2³+4√324= (primul radical acopera tot ex)
3.√2 la puterea 4+√289= (primul radical acopera tot ex)
4.√33+6√361= (primul radical acopera tot ex)
5.2²*3+8√441=(primul radical acopera tot ex)
6.√3²+3²√121=(primul radical acopera tot ex)

*=semnul ori

Answer 1

1 .  rad ( 36 + 3· 24 ) = rad ( 36 + 72 ) = √108 = √36 ·√3 = 6√3 
2.    rad ( 8 + 4 ·18 )  = rad ( 8 + 72) = √80 = √16·√5 = 4√5
3.    rad ( 16 + 17 ) =√33
4.    rad ( 33 + 6·19 ) = rad( 33 + 114 ) = √147 = √49·√3 = 7√3 
5.    rad ( 12  + 8 · 21 ) =  rad( 12  + 168) = √180 = √36·√5 =6√5 
6.    rad ( 9  + 9 ·11 ) = rad( 9 + 99 ) = √108 = √36 ·√3 = 6√3 

Answer 2

1. √(2²*3²+3√576)=√(4*9+3√2⁶*3²)=√(4*9+3*8*3)=√(4*9+3*24)=
=√(36+3*24)=√(36+72)=√108=√2²*3³=2*3√3=6√3
2. √(2³+4√324)=√(2*4+4√324)=√(8+4√324)=√80=√2⁴*5=4√5
3.√(2⁴+√289)=√(16+17)=√33
4.√(33+6√361)=√(33+114)=√147=√(3*7²)=7√3
5.√(2²*3+8√441)=√(12+8*21)=√(12+168)=√180=√(5*6²)=6√5
6.√(3²+3²√121) =√(9+9*11)=√(9+99)=√108=√(2²*3³)=2*3√3=6√3