Question

1)√27+√12-√75=?....2)2√8+3√18-13√2=?

Answer 1

$1). \sqrt{27} + \sqrt{12} - \sqrt{75} =3 \sqrt{3} +2 \sqrt{3} -5 \sqrt{3} =5 \sqrt{3} -5 \sqrt{3} =0 \\ 2).2 \sqrt{8} +3 \sqrt{18} -13 \sqrt{2} =2 \cdot 2 \sqrt{2} +3 \cdot 3 \sqrt{2} -13 \sqrt{2} = \\ =4 \sqrt{2} +9 \sqrt{2} -13 \sqrt{2} =13 \sqrt{2} -13 \sqrt{2} =0$

Answer 2

pt inceput ,,/"acesta va fi radicalul; nu am radical la computer
 /27 + /12 -/75 = 3/3 + 2/3 -5/3 = 0
Sper ca te-am ajutat