Question

1) 2x-1/1-x < (sau egal) cu 3x+2/1-2x
2) x^2-4x+3/x^2+3x+2 < ( sau egal ) cu 1
3) AB=2, AC=4, m (A) = 60° Să se afle lungimea medianei din A
4) AB=6, AC=10, Aria triunghiului ABC = 15 radical 2 Aflați BC

Answer 1

1) (2x-1)(1-2x)<\ (1-x)(3x+2)
2x-4x^2<\ 3x+2-3x^2-2x
-4x^2+3x^2+2x+2x<\ 2
-x^2+4x-2<\ 0
delta=b^2-4ac=16-8=8
x1=(-b+√delta)/2a=(-4+2√2)/-2= -2(2+√2)/-2=2+√2
x2=(-b-√delta)/2a=(-4-2√2)/-2= -2(2-√2)/-2= 2-√2

2) x^2-4x+3<\ x^2+3x+2
x^2-x^2-4x-3x+3-2<\ 0
-7x+1<\ 0
-7x<\ -1
x>\ 1/7
x€[1/7,+infinit)