Question

(1/3)ˆ0 + 1/3
1/2 -(1/2)^2
1-(1/4)^2
DAU COROANA!

Answer 1

Salut !

$( \frac{1}{3})^{0} + \frac{1}{3} = 1 + \frac{1}{3} = \frac{3}{3} + \frac{1}{3} = \frac{4}{3}$

$\frac{1}{2} - ( \frac{1}{2})^{2} = \frac{1}{2} - \frac{1}{4} = \frac{2}{4} - \frac{1}{4} = \frac{1}{4}$

$1 - ( \frac{1}{4})^{2} = \frac{1}{1} - \frac{1}{16} = \frac{16}{16} - \frac{1}{16} = \frac{15}{16}$

...............

Answer 2

Răspuns

Explicație pas cu pas:

(1/3)ˆ0 + 1/3=4/3

1/2 -(1/2)^2 =1/2-1/4=1/4

1-(1/4)^2=1-1/16=15/16