Question

1/√3-2 + 3/√3 aratati ca e numar intreg.

/=supra

Answer 1

$\dfrac{1}{\sqrt3 -2}+\dfrac{3}{\sqrt 3}=\dfrac{\sqrt3+2}{(\sqrt3-2)(\sqrt 3+2)}+\dfrac{3\sqrt 3}{3}=\dfrac{\sqrt3+2}{3-4}+\sqrt 3=\\ =-\sqrt 3-2+\sqrt 3= \boxed{-2}$