Question

1+3×(32^0×32^1×32^2:8^2:4^2-2^5) ESTE URGENT , AJUTATI-MA VA ROG FRUMOS

Answer 1

1+3(32^3÷8^2÷4^2-2^5)=
1+3[32^3÷(2^3)^2÷2^5]=
1+3[(2^5)^3÷2^6÷2^5]=
1+3(2^15÷2^6÷2^5)=
1+3×2^4=1+3×16=1+48=49

Answer 2

1+3*[1*32*32^2:(2^3)^2:(2^2)^2-2^5]=
1+3*(32^3:2^6:2^4-2^5)=
1+3*[(2^5)^3:2^6:2^4-2^5)]=
1+3*(2^15:2^6:2^4-2^5)=
1+3*(2^5-2^5)=
1+3*0=1