Question

[1, (3)+4,1 (6)]:[6,3-(3,25+1,5-0,4)-(0,75+1,2-1)] la puterea a 2

Answer 1

[1, (3)+4,1 (6)]:[6,3-(3,25+1,5-0,4)-(0,75+1,2-1)]²=
=[12/9+(416-41)/90]:(6,3-4,35-0,95)²=
=(4/3+375/90):(1)²=
=(4/3+25/6):1=
=(8+25)/6
=33/6
=11/2
=5,5