Question

1+3+5+...+(2×n+1) supra 2 ori [1+2+3+...+(n+1)
Aici n mai mare sau egal cu 2​

Answer 1

$\it \dfrac{1+3+5+\ ...\ +2n+1}{2(1+2+3+\ ...\ +n+1)} =\dfrac{(n+1)^2}{(n+1)(n+2)} =\dfrac{n+1}{n+2}$