Question

1 + 3 +5....+ 2011 va rog vreau rezolvarea nu doar raspunsul :(

Answer 1

cate numere sunt in sir:(2011-1):2+1=2010÷2+1=1005+1=1006
suma unei grupe:2011+1=2012
numărul de grupe:1006:2=503
rezultatul sumei:2012×503=1012036

Answer 2

   
[tex]\displaystyle \\ 1 + 3 +5+ \cdots + 2011 = ? \\ \text{Calculam numarul de termeni: } \\ \\ n = \frac{2011 - 1}{2}+1 = \frac{2010}{2}+1 = 1005+1 = \boxed{1006 ~termeni} \\ \\ \\ S = 1 + 3 +5+ \cdots + 2011 = \\ \\ = \frac{1006(2011+1)}{2}= \frac{1006\times2012}{2}= 1006\times 1006 = \boxed{\boxed{1006^2}}[/tex]