Question

1+3+5+.......+51=n2​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

 

$\displaystyle\bf\\1+3+5+...+51=n^2\\\\Calculam~numarul~termenilor~sumei.\\\\k=\frac{51-1}{2}+1=\frac{50}{2}+1=25+1=26\\\\S=\frac{26(51+1)}{2}=\frac{26\times52}{2}=26\times26=26^2\\\\26^2=n^2\\\\\implies~\boxed{\bf n=26}$