Question

1 3 si 4 plssss dau coroana​

Answer 1

1)

2 moli               n moli

NaOH + HCl --> NaCl + H2O

 1                           1

=> n = 2x1/1 = 2 moli NaCl

nr.moli = m/M, M.NaCl = 23+35,5 = 58,5 g/mol

=> m.NaCl = nxM = 2x58,5 = 117 g NaCl

3)

520g Zn impur .................... 100%

m.pura ................................. 75%

= 390g Zn pur

390g                         n moli

Zn + 2HCl --> ZnCl2 + H2

65                                   1

=> n = 390x1/65 = 6 moli H2

4)

250 kg impur .......................... 100%

m.pura ........................................ 80%

= 200 kg carbonat pur

200 kg               m kg

CaCO3 --toC--> CaO + CO2

100                       56

M.CaCO3 = 40+12+3x16 = 100 kg/kmol

M.CaO = 40+16 = 56 kg/kmol

=> m = 200x56/100 = 112 kg CaO