Question

1) {31990+ 1040:[ 504- 2400:( 67+53) x 20 ]} : 400
2) 3x345-{4050:27-25 + 13 +8-[7950 ::25+2x(484:4-15x6]}:5

Answer 1

A) {31990+1040:[504-2400:120×20]}:400 {31990+1040:[504-400]}÷400 {31990+1040:104}÷400 {31990+10}÷400 32000:400 80 B)3×345-{4050:27-25+13+8-[7950:25+2×636]}÷5 3×345-{4050:27-25+13+8-[318+1272]}÷5 3×345-{4050:27-25+13+8-1590}÷5 3×345-{150-25+13+8-1590}:5 3×345-1460:5 1035-292 743 Cred ca te am ajutat???

Answer 2

{31990+1040÷[504-2400÷(67+53)×20]}÷400= =[31990+1040÷(504-2400÷120×20)]÷400= =[31990+1040÷(504-20×20)]÷400= =[31990+1040÷(504-400)]÷400= =(31990+1040÷104)÷400= =(31990+10)÷400= =32000÷400= =80 3×345-{4050÷27-25+13+8-[7950÷25+2×(484÷4-15×6]}÷5= =3×345_{4050÷27-25+13+8-[7950÷25+2×(121-90)]}÷5= =3×345-[150-25+13+8-(318+2×31)]÷5= =1035-(150-25+13+8-318+62)÷5= =1035-(-110)÷5= =1035+22=1057